SOLUTION: Two squares have sides of lengths x cm and( 2x + l) cm. The sum of the perimeters of the two squares equals 88 cm. The length of each side of the larger square is (a) 7 (b) 15 (

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Question 288306: Two squares have sides of lengths x cm and( 2x + l) cm. The sum of the perimeters of the two squares equals 88 cm. The length of each side of the larger square is
(a) 7 (b) 15 (c) 29 (d) 57 (e) none of these
Answer by stanbon(75887) About Me  (Show Source):
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Two squares have sides of lengths x cm and( 2x + l) cm. The sum of the perimeters of the two squares equals 88 cm. The length of each side of the larger square is
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1st perimeter = 4x cm
2nd perimeter = 4(2x+1) = 8x+4 cm
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Equation:
4x + 8x+4 = 88
12x = 84
x = 7
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1st side: x = 7
2nd side: 2x+1 = 15
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Cheers,
Stan H.






(a) 7 (b) 15 (c) 29 (d) 57 (e) none of these