SOLUTION: The length of a photograph is 1 cm less than twice the width. The area is 45cm squared. Find the dimensions of the photograph. the problem must be solved algebracly using the q

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The length of a photograph is 1 cm less than twice the width. The area is 45cm squared. Find the dimensions of the photograph. the problem must be solved algebracly using the q      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 281243: The length of a photograph is 1 cm less than twice the width. The area is 45cm squared. Find the dimensions of the photograph.
the problem must be solved algebracly using the quadratic formula, factoring or anything like that. thanks
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Let width be w and length be l.
l+=+2w-1
Area+=+Length+%2A+Width
45+=+%282w-1%29w
45+=+2w%5E2+-w
0+=+2w%5E2+-+w+-+45
0+=+%282w+%2B9%29%28w+-+5%29
so either w-5 =0 or 2w+9=o
w = 5 or w = -9/2
since a distance can't be nagative, width = 5
so length = 2*5-1 = 9
Does 9*5 = 45??