Question 267841: if the perimeter of a rectangle is 460 ft the length of the rectangle is 30 more than the wight. how to you find the wight?
Answer by PRMath(133)   (Show Source):
You can put this solution on YOUR website! The perimeter is the measure all around a shape. In other words, for a rectangle, you would add the following:
Length + Length + Width + Width = Perimeter. You can rewrite that with "L" for length and "W" for width, which will be:
L + L + W + W = P
You are told that the length ("L") is 30 more than the width ("W").
So, the Length is 30 more than the width, which translated says:
The Length: L
is: =
30 more than the width: 30 + W
This is: L = 30 + W
Let's use L + L + W + W = P and everywhere you have an "L", let's replace it with what we know about "L" which is L = 30 + W.
Also, we will plug in what we know about "P" (perimeter). We know the perimeter is 460.
L + L + W + W = P (perimeter equation)
30 + W + 30 + W + W + W = 460 (see where we put in 30 + W everywhere there was an "L" variable?)
60 + 4W = 460 (see where we combined like terms?)
4W = 400 (subtract 60 from both sides to start to isolate the W)
W = 100 (divide both sides by 4 to isolate the W)
Now we know that the width is 100.
If the width is 100, then the length is 30 more than the width or: 100 + 30 which is 130.
Does this all work out? Let's go back to our original equation and plug in what we know:
L + L + W + W = P
130 + 130 + 100 + 100 = 460
Our info checks out. :-)
I hope this helps you.
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