SOLUTION: im having a hard time with this problem,please help! if the length of a rectangular parking lot is 20 meters less than twice its width,and the perimeter is 800 meters,find the leng

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Question 262852: im having a hard time with this problem,please help! if the length of a rectangular parking lot is 20 meters less than twice its width,and the perimeter is 800 meters,find the length of the parking lot.
Found 2 solutions by josmiceli, dabanfield:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let j = the length in meters
Let k = the width in meters
Let p = perimeter in meters
given:
j+=+2k+-+20 m
p+=+800 m
-------------------
The problem is to find j
The formula for the perimeter of a rectangle is:
p+=+2j+%2B+2k
800+=+2j+%2B+2k
Substitute the given value for j in this equation
800+=+2%2A%282k+-+20%29+%2B+2k
800+=+4k+-+40+%2B+2k
6k+=+840
k+=+140 m
Now substitute this value in given equation
j+=+2%2A140+-+20
j+=+280+-+20
j+=+260
The length of the parking lot is 260 m
check answer:
800+=+2j+%2B+2k
800+=+2%2A260+%2B+2%2A140
800+=+520+%2B+280
800+=+800
OK

Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
im having a hard time with this problem,please help! if the length of a rectangular parking lot is 20 meters less than twice its width,and the perimeter is 800 meters,find the length of the parking lot.
Let w be the width and l the length of the parking lot. Then we have:
1.) Perimeter = 2*w + 2*l = 800
2.) l = 2w - 20
Let's rewrite these two equations:
1.) 2w + 2l = 800
2.) 2w - l = 20
Subtracting equation 2.) from equation 1.) we have:
3*l = 780
l = 780/3 = 260
Calculate w from 2.:
2*w - 260 = 20
2w = 280
w = 140