Question 262612: Clint is constructing two adjacent rectangular dog pens. Each pen will be three times as long as it is wide, and the pens will share a common long side. If clint has 65 ft of fencing, what are the dimensions of each pen?
Found 3 solutions by mananth, ikleyn, greenestamps:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! Clint is constructing two adjacent rectangular dog pens. Each pen will be three times as long as it is wide, and the pens will share a common long side. If clint has 65 ft of fencing, what are the dimensions of each pen?
Let width be x
Length =3x
Perimeter =3x + 3x + 3x + 3x + x + x = 14x
14x=65
X=4.64 ft
Length= 13.92ft
mananth@hotmail.com
Answer by ikleyn(53742)  (Show Source):
You can put this solution on YOUR website! .
Clint is constructing two adjacent rectangular dog pens. Each pen will be three times as long as it is wide,
and the pens will share a common long side. If clint has 65 ft of fencing, what are the dimensions of each pen?
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The solution in the post by @mananth is incorrect conceptually: he incorrectly setup his governing equation.
I came to bring a correct solution.
Let x be width of the pens, in feet.
Then their length is 3x feet, according to the problem.
We have 3 long sides of the length 3x ft each, and 4 short sides of the length x ft each.
So, the total length of all dimensions is 3*(3x) + 4x.
Therefore, the equation for the total fence length is
3*(3x) + 4x = 65 feet.
Simplify and find x
13x = 65,
x = 65/13 = 5 feet.
ANSWER. The dimensions of each pen are 5 ft x 15 ft.
Solved correctly.
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Thanks to tutor @greenestamps for noticing my typo.
I just fixed it.
Answer by greenestamps(13326)  (Show Source):
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