Question 25160: One number is 10 more than the other number. Twice the smaller number is 13 more than the larger number. What are the numbers?
please help I need it by today thank you
Answer by rapaljer(4671)   (Show Source):
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Okay, here we go:
Let x = the smaller number
x+10 = larger number
"Twice smaller IS larger number plus 13 more."
2x = x+10 + 13
2x = x + 23
Subtract x from each side:
2x -x = x-x +23
x= 23= Smaller number
x+10 = 33= Larger number
Check: Twice the smaller number is 46 which is 13 more than 33. It checks.
R^2 at SCC
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