SOLUTION: The base of an isosceles triangle is 12 cm longer than each of its equal legs. a second isosceles triangle whose perimeter is 85 cm has abase that is 15 cm shorter than the base of
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Question 239047: The base of an isosceles triangle is 12 cm longer than each of its equal legs. a second isosceles triangle whose perimeter is 85 cm has abase that is 15 cm shorter than the base of the first triangle. each of the equal legs of the second triangle is 8 cm longer than each leg of the first. how long are the three sides of each triangle?
Could you help me to find the equation you would use to solve this problem? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The base of an isosceles triangle is 12 cm longer than each of its equal legs.
a second isosceles triangle whose perimeter is 85 cm has a base that is 15 cm shorter than the base of the first triangle.
each of the equal legs of the second triangle is 8 cm longer than each leg of the first.
how long are the three sides of each triangle?
:
label the 1st triangle equal sides as x, then the base = (x+12)
label the 2nd triangle equal sides as (x+8), then the base (x+12)-15 = (x-3)
:
The perimeter equation of the 2nd triangle:
2(x+8) + (x-3) = 85
2x + 16 + x - 3 = 85
3x + 13 = 85
3x = 85 - 13
3x = 72
x =
x = 24
:
Now you should be able to find the length of the other sides of both triangles
