SOLUTION: The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width 10 inches, what is the screen length and width?

Click here to see ALL problems on Geometry Word Problems

Question 228526: The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width 10 inches, what is the screen length and width?
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width by 10 inches, what is the screen length and width?

Step 1. Perimeter P means adding up all 4 sides of a rectangle.

Step 2. Let w be the width.

Step 3. Let 2w+10 be the length since the length exceeds twice its width by 10 inches

Step 4. Then, P=w+w+2w+10+2w+10=6w+20=272

Step 5. Solving yields the following steps:

Subtract 20 from both sides of the equation

Divide by 6 to both sides of the equation

and . Then P=2(42+94)=272 which is a true statement.

Step 6. ANSWER: The width is 42 inches and the length is 94 inches.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J