SOLUTION: Where is the center of the circle given by the equation (x + 7)2 + (y

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Question 227118: Where is the center of the circle given by the equation (x + 7)2 + (y - 5)2 = 16?
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
This looks like the vertex form of the equation for a circle.

The general form of that should be:

(x-h)^2 + (y-k)^2 = r^2

where:

(h,k) is the (x,y) coordinates of the center of the circle.

Since -h = +7, then h must be -7.

Since -k = -5, then k must be 5.

Center of your circle is at x,y) = (-7,5)

To graph your circle, we need to solve for y.

Your equation is:

(x + 7)^2 + (y - 5)^2 = 16

Subtract (x+7)^2 from both sides to get:

(y-5)^2 = 16 - (x+7)^2)

Take the square root of both sides of the equation to get:

y-5 = +/-

Add 5 to both sides of the equation to get:

y = 5 +/-

graph of your equation looks like.....

SOLUTION: Where is the center of the circle given by the equation (x + 7)2 + (y - 5)2 = 16?