SOLUTION: the perimeter of a rectangular field is 1,200 feet and the field is 50 feet longer than it is wide. what is the length, i feet, of the field?

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Question 223573: the perimeter of a rectangular field is 1,200 feet and the field is 50 feet longer than it is wide. what is the length, i feet, of the field?
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangular field is 1,200 feet and the field is 50 feet longer than it is wide. what is the length, in feet, of the field?

Step 1. Perimeter P means adding up all 4 sides of the rectangle.

Step 2. Let w be the width.

Step 3. Let w+50 be the length.

Step 4. Then, P=1200=w+w+w+50+w+50.

Step 5. Solving leads to the following steps...

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: w=275.
  • Graphical form: Equation 1200=w%2Bw%2Bw%2B50%2Bw%2B50 was fully solved.
  • Text form: 1200=w+w+w+50+w+50 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+1200=w%2Bw%2Bw%2B50%2Bw%2B50+%29
    For tutors: simplify_cartoon( 1200=w+w+w+50+w+50 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at 1200=w%2Bw%2Bw%2Bhighlight_red%28+50+%29%2Bw%2Bhighlight_red%28+50+%29.
Added fractions or integers together
It becomes 1200=w%2Bw%2Bw%2Bhighlight_green%28+100+%29%2Bw.
Look at 1200=w%2Bw%2Bw%2Bhighlight_red%28+100+%29%2Bw.
Moved 100 to the right of expression
It becomes 1200=w%2Bw%2Bw%2Bw%2Bhighlight_green%28+100+%29.
Look at .
Eliminated similar terms highlight_red%28+w+%29,highlight_red%28+w+%29,highlight_red%28+w+%29,highlight_red%28+w+%29 replacing them with highlight_green%28+%281%2B1%2B1%2B1%29%2Aw+%29
It becomes 1200=highlight_green%28+%281%2B1%2B1%2B1%29%2Aw+%29%2B100.
Look at .
Added fractions or integers together
It becomes 1200=%28highlight_green%28+4+%29%29%2Aw%2B100.
Look at 1200=highlight_red%28+%28highlight_red%28+4+%29%29%2Aw+%29%2B100.
Remove unneeded parentheses around factor highlight_red%28+4+%29
It becomes 1200=highlight_green%28+4+%29%2Aw%2B100.
Look at 1200=highlight_red%28+4%2Aw%2B100+%29.
Moved these terms to the left highlight_green%28+-4%2Aw+%29,highlight_green%28+-100+%29
It becomes 1200-highlight_green%28+4%2Aw+%29-highlight_green%28+100+%29=0.
Look at highlight_red%28+1200+%29-4%2Aw-highlight_red%28+100+%29=0.
Added fractions or integers together
It becomes highlight_green%28+1100+%29-4%2Aw=0.
Look at highlight_red%28+1100+%29-4%2Aw=0.
Moved 1100 to the right of expression
It becomes -4%2Aw%2Bhighlight_green%28+1100+%29=0.
Look at highlight_red%28+-4%2Aw%2B1100+%29=0.
Solved linear equation highlight_red%28+-4%2Aw%2B1100=0+%29 equivalent to -4*w+1100 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: w=275.

Universal Simplifier and Solver


Done!



w=275 then w%2B50=325 and P=2%28275%2B325%29=1200 which is a true statement.

Step 6. ANSWER: The length of the field is 325 yards.

I hope the above steps were helpful.

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Good luck in your studies!

Respectfully,
Dr J