SOLUTION: A rectangle's length is 20 less than 3 times its width. The perimeter of the rectangle is 80. What are the dimensions of the length and the width?
I'm pretty sure that the answe
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I'm pretty sure that the answe
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Question 208617: A rectangle's length is 20 less than 3 times its width. The perimeter of the rectangle is 80. What are the dimensions of the length and the width?
I'm pretty sure that the answer is 25 x 15 from trial and error, but I do not know how to solve it algebraically. Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website!
Let length = 3x - 20
Let width = x
The perimeter is 80
Use the formula: P = 2L + 2W as step one.
Here is the set up:
80 = 2(3x - 20) + 2(x)
When you find x, this will be your width. Then go back to 3x - 20, plug your value for x and simplify to find your length.
Can you finish now?
