SOLUTION: In a triangle, the first angle measures 3 times the second and the third measures 20 degress less than the second. find each angle's measure.
Question 204538This question is from textbook
: In a triangle, the first angle measures 3 times the second and the third measures 20 degress less than the second. find each angle's measure. This question is from textbook
You can put this solution on YOUR website! first angle = x
second angle = y
third angle = z
x = 3y
z = y - 20
in a triangle, the sum of its angles are 180 degrees
x + y + z = 180
3y + y + y - 20 = 180
5y - 20 = 180
5y = 180 + 20
5y = 200
y = 200/5
y = 40
x = 3y = 3 * 40 = 120
z = y - 20 = 40 - 20 = 20
so,
the first angle is 120 degrees
the second angle is 40 degrees
the third angle is 20 degrees
You can put this solution on YOUR website! In a triangle, the first angle measures 3 times the second and the third measures 20 degress less than the second. find each angle's measure.
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To answer this question, you need to know that the sum of the interior angles of any triangle is 180 degrees.
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Let x = measure of second angle
then
3x = measure of first angle
3x-20 = measure of third angle
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x + 3x + 3x-20 = 180
7x-20 = 180
7x = 200
x = 28.57 degrees (second angle)
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First angle:
3x = 3(28.57) = 85.71 degrees (first angle)
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Third angle:
3x-20 = 3(28.57)-20 = 65.71 degrees (third angle)