SOLUTION: 1. A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third side

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Question 196649: 1. A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third side is 4 meters more than the first side. Find the length in meters of each side of the triangular region.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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1. The perimeter of the triangle is 49 meters.
The second side is one-fourth of the first side in length.
The third side is 4 meters more than the first side.
Find the length in meters of each side of the triangular region.
:
three sides, a, b, c
:
Perimeter
a + b + c = 49
:
"The second side is one-fourth of the first side in length."
b = .25a
:
" The third side is 4 meters more than the first side."
c = a + 4
:
Substitute for b and c in the perimeter equation:
a + .25a + (a+4) = 49
2.25a = 49 - 4
2.25a = 45
a = 45%2F2.25
a = 20
then
b = .25(20)
b = 5
and
c = 20 + 4
c = 24
;
;
Check solution
20 + 5 + 24 = 49
:
Sorry about that!!