SOLUTION: The Great Pyramid of Cheops has a square base of 771 ft on a side and a height of 486 ft. How many apartments 35 ft x 20 ft x 8 ft would be needed to have a volume equivalent to

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Question 193536This question is from textbook
: The Great Pyramid of Cheops has a square base of 771 ft on
a side and a height of 486 ft. How many apartments 35 ft x
20 ft x 8 ft would be needed to have a volume equivalent to
that of the Great Pyramid’s?
Please show me how to work this problem. Thank you. This question is from textbook

Found 2 solutions by vleith, RAY100:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
First find the volume in a square pyramid.
http://www.mathsteacher.com.au/year10/ch14_measurement/25_pyramid/21pyramid.htm
V%5Bp%5D+=+l%5E2%2Ah+%2F3
V%5Bp%5D+=+771%5E2+%2A+486+%2F+3+
V%5Bp%5D+=+96299442 cubic feet
Next find the volume in one cube shaped apartment
V%5Ba%5D+=+l+%2A+w+%2A+h+
V%5Ba%5D+=+35+%2A+20+%2A+8
v%5Ba%5D+=+5600+ cubic feet
Now see how times larger in volume the pyramid is compared to the apartment
TimesBiggerInVolume+=+V%5Bp%5D+%2FV%5Ba%5D
TimesBigger+=+96299442+%2F5600+
TimesBigger+=+17183.83+
So the volume of 17183 complete apartments fits in there.

Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Volume of pyramid =(1/3)*Base*Height=(1/3)(771^2)(486)=96,299,442
Volume of rect solid is l*w*h=35*20*8=5600
ratio is 96,299,442/5600=17,196.3