SOLUTION: Can you please help me with this word problem for some reason Im not understanding the concept of figuring these problems.
The lenght of a rectangular picture is 5 inches grea
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The lenght of a rectangular picture is 5 inches grea
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Question 185243: Can you please help me with this word problem for some reason Im not understanding the concept of figuring these problems.
The lenght of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame.
thanks, Found 2 solutions by stanbon, ankor@dixie-net.com:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The length of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame.
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Let the width be "x".
Then length = "2x+5"
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Perimeter = 2(length + width)
112 = 2(2x+5 + x)
56 = 3x+5
3x = 51
x = 17 inches (width)
2x+5 = 2*17+5 = 34+5 = 39 inches (length)
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Cheers,
Stan H.
You can put this solution on YOUR website! Let x = the width
"L" = the length
:
Just write an equation for what it says:
:
"The length of a rectangular picture is 5 inches greater that twice the width.
L = 2x + 5
:
" If the perimeter is 112 inches,"
twice the length + twice the width = 112
2L + 2x = 112
Simplify, divide equation by 2; the results:
L + x = 56
:
From the 1st statement, replace L with (2x+5)
(2x+5) + x = 56
subtract 5 from both sides
2x + x = 56 - 5
3x = 51
x =
x = 17 in is the width
then
L = 2(17) + 5
L = 34 + 5
L = 39 in is the length
;
:
Check solution by finding the perimeter
2(39) + 2(17) =
78 + 34 = 112, confirms our solution
;
Did this make sense?
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