SOLUTION: The length of a rectangle exceeds twice its width by 4 cm. The perimeter of the rectangle is 68 cm. Find the length and the width. (Hint: P=2l+2w)
Can you please help me wit
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Can you please help me wit
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Question 183384: The length of a rectangle exceeds twice its width by 4 cm. The perimeter of the rectangle is 68 cm. Find the length and the width. (Hint: P=2l+2w)
Can you please help me with this question? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The length of a rectangle exceeds twice its width by 4 cm. The perimeter of the rectangle is 68 cm. Find the length and the width. (Hint: P=2l+2w)
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Perimeter = 2(L + W)
68 = 2((2W+4)+W)
34 = 3W + 4
30 = 3W
W = 10 cm (width)
L = 2W+4 = 2*10+4 = 24 cm (length)
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Cheers,
Stan H.
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