SOLUTION: The perimeter of a rectangular yard is 290 feet. If its length is 25 feet greater than its width, what are the dimensions of the yard. Use the five step method to solve.

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Question 177577: The perimeter of a rectangular yard is 290 feet. If its length is 25 feet greater than its width, what are the dimensions of the yard. Use the five step method to solve.
Found 2 solutions by Mathtut, checkley75:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
again I will leave the 5-steps to you
:
P=2L+2W...eq 1
:
L=W+25....eq 2
:
P=290.....eq 3
:
take values of eq 2 and 3 and plug them into eq 1
:
290=2(W+25)+2W
:
290=2W+50+2W......distributed right side
:
240=4W
:
highlight%28W=60%29feet
:
L=W%2B25=60%2B25=highlight%2885%29feet
:
Yard is 60x85
:

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
2L+2W=290
L=W+25
2(W+25)+2W=290
2W+50+2W=290
4W=290-50
4W=240
W=240/4
W=60 ans.
L=60+25=85 ans.
Proof:
2*85+2*60=290
160+120=290
290=290