SOLUTION: The perimeter of one square is 36 inches more than the perimeter of a second square, and the area of the first square is 243 square inches more than the area of the second square.

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Question 177473: The perimeter of one square is 36 inches more than the perimeter of a second square, and the area of the first square is 243 square inches more than the area of the second square. Find the area of the larger square.
I have tried working this out and I came up with the side of the larger square being x +9,and I don't know if I'm on the right track. I know a perimeter is 4s and area is s^2, but I don't know exactly what to do, and need step by step instructions. Thanks!!!
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
We know thatL%5B1%5D=W%5B1%5D} andL%5B2%5D=W%5B2%5D}
:
so 4L%5B1%5D=4L%5B2%5D%2B36--->L%5B1%5D=L%5B2%5D%2B9.....eq 1
:
and for the area we know:
:
L%5B1%5D%5E2=L%5B2%5D%5E2%2B243....eq 2
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so now lets plug L%5B1%5D's value from eq 1 into eq 2
:
%28L%5B2%5D%2B9%29%5E2=L%5B2%5D%5E2%2B243
:
L%5B2%5D%5E2%2B18L%5B2%5D%2B81=L%5B2%5D%2B243
:
18L%5B2%5D=162
:
highlight%28L%5B2%5D=9%29inches
:
highlight%28L%5B1%5D%29=L%5B2%5D%2B9=9%2B9=highlight%2818%29inches
:
highlight%2818%2A18=324%29 sq inches for large square