SOLUTION: how do i solve the quadratic equasion x^2+11x-80=0

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Question 174686: how do i solve the quadratic equasion x^2+11x-80=0
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve the quadratic equasion x^2+11x-80=0
---------------------
Factor:
(x+16)(x-5) = 0
x = -16 or x = 5
=======================
Cheers,
Stan H.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I like to use the method called "completing the square"
To do this you first get the constant term on the
other side
(1) Add 80 to both sides
x%5E2+%2B+11x+-+80+=+0
x%5E2+%2B+11x+=+80
(2) Now divide the coefficient of the x term by 2,
then square it and add this to both sides
x%5E2+%2B+11x+%2B+%2811%2F2%29%5E2+=+80+%2B+%2811%2F2%29%5E2
The purpose of this is to make the left side a perfect
square, which it is. It might be hard to see, but I
can rewrite this as
%28x+%2B+11%2F2%29%5E2+=+80+%2B+%2811%2F2%29%5E2
Now I want to express 80 as 320%2F4
%28x+%2B+11%2F2%29%5E2+=+320%2F4+%2B+121%2F4
%28x+%2B+11%2F2%29%5E2+=+441%2F4
Now take the square root of both sides
x+%2B+11%2F2+=+0+%2B-sqrt%28441%29%2F2
x+=+%28-11+%2B+21%29%2F2
x+=+5
and
x+=+%28-11+-+21%29%2F2
x+=+-16
check answers:
x%5E2+%2B+11x+-+80+=+0
5%5E2+%2B+11%2A5+-+80+=+0
25+%2B+55+-+80+=+0
0+=+0
OK
%28-16%29%5E2+%2B+11%2A%28-16%29+-+80+=+0
256+-+176+-+80+=+0
256+-+256+=+0
0+=+0
OK