SOLUTION: a carpet layer wishes to determine the cost of carpeting a rectangular room whose perimeter is 52 feet. Suppose that the length of the room is 4 feet more than its width. Find (a)

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Question 165764This question is from textbook
: a carpet layer wishes to determine the cost of carpeting a rectangular room whose perimeter is 52 feet. Suppose that the length of the room is 4 feet more than its width. Find
(a) the length and width of the room
(b) the cost of the carpet if it costs $18.95 per square yard
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Found 2 solutions by Mathtut, jojo14344:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
so we are given P-perimeter as 52 feet we know that P=2(L+W) the length or L is 4 more fee than the width L=W+4 so substitution our given and the L value in the 2nd equation into our perimeter formula we get 52=2((W+4)+W) lets distribute the right side 52=4W+8 so subtract 8 both sides and 4W=44 divide each side by 4 and W=11 L=W(11)+4 so L=15
a. width is 11 feet
length is 15 feet
b A=15 times 11=165 sq ft but we must divide this by 9 to get square yards
so 165/9=18.33 sq yards
so 18.33 sq yd multiplied by cost per yard of $18.95 equals $347.35 as being the cost of the carpet for this given room

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

a) Remember: P=2%28L%2BW%29
But, L=W%2B4, length 4 ft more than its width
Then, P=2%28W%2B4%2BW%29
52=2%282W%2B4%29=4W%2B8
4W=52-8=44 ---> cross%284%29W%2Fcross%284%29=cross%2844%2911%2Fcross%284%29
highlight%28W=11ft%29
So, highlight%28L=11%2B4=15ft%29
Check,
52ft=2%2815%2B11%29
52=2%2826%29
52ft=52ft, good
b) Remember: A=L%2AW
A=11%2A15=165ft%5E2
Take note: 1ft%5E2=0.111111yd%5E2
Then,
=
=highlight%28347.42%29 ----> cost to carpet the whole room
Thank you,
Jojo