SOLUTION: how would this be factored? 3x^3y^2-3x^2y^2+3xy^2

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Question 157749: how would this be factored?
3x^3y^2-3x^2y^2+3xy^2

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
3x^3y^2-3x^2y^2+3xy^2
3XY^2(X^2-X+1)