SOLUTION: The perimeter of an isosceles triangle is 70dm. If the length of a leg of the triangle is 5dm less than twice the length of the base, find the lengths of the sides of the triangle.
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Question 150588: The perimeter of an isosceles triangle is 70dm. If the length of a leg of the triangle is 5dm less than twice the length of the base, find the lengths of the sides of the triangle. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! A) 2L+b=70
B) L=2b-5
.
A)
2(2b-5)+b=70 Substitute 2b-5 for L.
4b-10+b=70
5b=80
b=16 dm
.
B)
L=2*16 -5
=27 dm
.
27+27+16=70
.
Ed
