Question 142530This question is from textbook Intermediate Algebra
: PLEASE HELP !
George built a rectangular pen for his rabbit such that the length is 7ft. less than twice the width. If the perimeter is 40ft. what are the dimensions of the pen?
This question is from textbook Intermediate Algebra
Answer by jojo14344(1513)   (Show Source):
You can put this solution on YOUR website! Well, simply we go to the formula for finding the perimeter(P) of a rectangle,
P=2(length + width)---------- eqn 1
We assigned "x" as the width measurement since it is unknown,and length= 2x-7ft,
being 7 less twice the width, make sense right?
Therefore substituting,
40= 2(2x-7 +x)
40=6x-14
x=(40+14)/6
x=9 ft, Width
And, L=2x-7=2(9)-7= 11ft, Length
In doubt? go back eqn 1,
P=2(L+W)
40=2(11+9)
40=2(20)
40=40 cool!
Thank you,
Jojo
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