SOLUTION: I need help solving this word problem. Thanks a ton! The so-called golden rectangle is said to be extremely pleasing visually and was used often by ancient Greek and Roman arch

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Question 131834This question is from textbook
: I need help solving this word problem. Thanks a ton!
The so-called golden rectangle is said to be extremely pleasing visually and was used often by ancient Greek and Roman architects. The length of a golden rectangle is approximately 1.6 times the width. Find the dimensions of a golden rectangle if its area is 9000 m^2. This question is from textbook

Found 2 solutions by edjones, TakeATuition.com:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Let w=width; L=1.6w
L*w=A
1.6w*w=9000
1.6w^2=9000
w^2=9000/1.6
w^2=5625
w=75 m Take sqrt of each side.
L=75*1.6=120 m
.
Ed

Answer by TakeATuition.com(57) About Me  (Show Source):
You can put this solution on YOUR website!
SOLUTION -

Let the width be x meter
then the length will be 1.6%2Ax= 16x%2F10=8x%2F5
area of golden rectangle=9000+m%5E2
length*breadth=9000
%288x%2F5%29%2Ax=9000
8x%5E2%2F5=9000
%288x%5E2%2F5%29%2A5=9000%2A5
8x%5E2%2F8=45000%2F8
x%5E2=5625
x=sqrt%285625%29
x=75
now width=x=75 meter
and length=8x%2F5=%288%2A75%29%2F5=120 meter

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