SOLUTION: The Diaz family went to the Dizzy Amusement park. The tickets cost $73 for 3 adults and 5 children. The Anderson family paid $93 for 7 adults and 2 children. The Owens-Faulkner fam
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-> SOLUTION: The Diaz family went to the Dizzy Amusement park. The tickets cost $73 for 3 adults and 5 children. The Anderson family paid $93 for 7 adults and 2 children. The Owens-Faulkner fam
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Question 122354: The Diaz family went to the Dizzy Amusement park. The tickets cost $73 for 3 adults and 5 children. The Anderson family paid $93 for 7 adults and 2 children. The Owens-Faulkner family reunion will need tckets for 55 adult and 53 children. What will the total cost for the Owens-Faulkner family reunion to enter the amusement park?[No group discounts were given.] Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The Diaz family went to the Dizzy Amusement park. The tickets cost $73 for 3 adults and 5 children. The Anderson family paid $93 for 7 adults and 2 children.
:
Use the first two statements of find the individual price for adults & children
:
Let a = adult's price
and
c = children's price
:
Diaz equation:
3a + 5c = 73
:
Anderson equation:
7a + 2c = 93
:
We can use elimination to solve this: Mult D eq by 2 and A eq by 5
35a + 10c = 465
6a + 10c = 146
---------------- subtracting eliminates c, find a
29a + 0c = 319
a =
a = $11, cost of 1 adult
:
Use 3a + 5c = 73 to find c; substitute 11 fora
3(11) + 5c = 73
5c = 73 - 33
5c = 40
c =
c = $8, cost per child
:
Check solutions in 7a + 2c = 93
7(11) + 2(8) =
77 + 16 = 93 confirms our solution
:
The Owens-Faulkner family reunion will need tickets for 55 adult and 53 children. What will the total cost for the Owens-Faulkner family reunion to enter the amusement park?[No group discounts were given.]
:
It's an easy task to find the cost of the above family now.
55(11) + 53(8) =
605 + 424 = $1029 for the O-F family
