SOLUTION: Sisters Helen and Anne live 332 miles apart. For Thanksgiving, they met at their other sister's house partway between their homes. Helen drove 3.2 hours and Anne drove 2.8 hours.

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Question 1208248: Sisters Helen and Anne live 332 miles apart. For Thanksgiving, they met at their other sister's house
partway between their homes. Helen drove 3.2 hours and Anne drove 2.8 hours. Helen's average speed
was four miles per hour faster than Anne's. Find Helen's average speed and Anne's average speed.
Found 3 solutions by josgarithmetic, timofer, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
RATE%2ATIME=DISTANCE

Helen went distance of %28r%2B4%29%283.2%29miles.
Anne went distance of %28r%29%282.8%29miles.

The sum of distances must be 332 miles.
%28r%2B4%29%283.2%29%2B%28r%29%282.8%29=332.
Solve!

Answer by timofer(104) About Me  (Show Source):
You can put this solution on YOUR website!
v the speed for cross%28Helen%29 Ann
3.2%28v%2B4%29%2B2.8v=332
3.2v%2B12.8%2B2.8v=332
6v=319.2
v=53.2

Does this work?
3.2%2A53.2%2B3.2%2A4%2B2.8%2A53.2
170.24%2B12.8%2B148.96
332 so this worked.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Sisters Helen and Anne live 332 miles apart. For Thanksgiving, they met at their other sister's house
partway between their homes. Helen drove 3.2 hours and Anne drove 2.8 hours. Helen's average speed
was four miles per hour faster than Anne's. Find Helen's average speed and Anne's average speed.

There's something WRONG with one of the responses.

Let Helen’s average speed be S
Then Anne’s average speed = S - 4
Helen’s distance covered: 3.2S
Anne’s distance covered: 2.8(S - 4) = 2.8S - 11.2
Since together, they both covered a total of 332 miles, we get the following DISTANCE
equation: 3.2S + 2.8S - 11.2 = 332
                          6S = 343.2
     Helen’s speed, or 

             Anne’s speed = 57.2 - 4 = 53.2 mph