SOLUTION: The perimeter of the rectangular playing field is 538 yards. The length of the field is 6 yards less than quadruple the width. What are the dimensions of the playing field?

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Question 1203492: The perimeter of the rectangular playing field is 538 yards. The length of the field is 6 yards less than quadruple the width. What are the dimensions of the playing field?
Found 2 solutions by math_tutor2020, MathLover1:
Answer by math_tutor2020(3817) (Show Source):
You can put this solution on YOUR website!

w = width
4w = quadruple the width
4w-6 = subtract off 6 = length

2*(length + width) = perimeter of rectangle
2*( (4w-6) + w ) = 538
2*( 5w-6 ) = 538
10w-12 = 538
10w = 538+12
10w = 550
w = 550/10
w = 55
4w-6 = 4*55-6 = 220-6 = 214

The rectangle is 55 yards by 214 yards

Check:
2*(length+width) = perimeter
2*(214+55) = 538
2*(269) = 538
538 = 538
The answers are confirmed.

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Answers:
width = 55 yards
length = 214 yards

Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!

The perimeter of the rectangular playing field is 538 yards. The length of the field is 6 yards less than quadruple the width. What are the dimensions of the playing field?
let the length of the field be and the width
The perimeter of the rectangular playing field is:

...eq.1

if the length of the field is yards less than quadruple the width, we have

substitute in eq.1

then

the dimensions of the playing field: by

check the perimeter:
...eq.1

=> true

SOLUTION: The perimeter of the rectangular playing field is 538 yards. The length of the field is 6 yards less than quadruple the width. What are the dimensions of the playing​ field?

SOLUTION: The perimeter of the rectangular playing field is 538 yards. The length of the field is 6 yards less than quadruple the width. What are the dimensions of the playing field?