SOLUTION: A flowerbed is a rectangle with a semicircle at each end. The total length of the flowerbed is 50 feet and the width is 14 feet. a) Sketch the flowerbed and determine its area.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: A flowerbed is a rectangle with a semicircle at each end. The total length of the flowerbed is 50 feet and the width is 14 feet. a) Sketch the flowerbed and determine its area.       Log On

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Question 1200873: A flowerbed is a rectangle with a semicircle at each end.
The total length of the flowerbed is 50 feet and the width is 14 feet.
a) Sketch the flowerbed and determine its area.
b) A gardener can plant 10 plants per square yard. How many plants should
he buy for this flowerbed?
c) The fertilizer he will apply should be spread at a rate of 2 kg per 30 m2.
About how much fertilizer will he need for this garden?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A flowerbed is a rectangle with a semicircle at each end.
The total length of the flowerbed is 50 feet and the width is 14 feet.
a) Sketch the flowerbed and determine its area.
The radius of the semicircles is half the width, 7 ft
The length of the rectangular portion, 50 - 14 = 36 fit
A = pi%2A7%5E2 + (14 * 36)
A = 153.938 + 504
A = 657.938 ~ 658 sq ft
:
b) A gardener can plant 10 plants per square yard. How many plants should
he buy for this flowerbed?
convert sq/ft to sq/yards
658/9 = 73.1 is the area in sq yards.
About 73 * 10 = 730 plants in this area
;
c) The fertilizer he will apply should be spread at a rate of 2 kg per 30 m2.
About how much fertilizer will he need for this garden?
Convert 73 sq yds to sq meters
.8361 * 73 ~ 61 sq/meters
2 kg per 30 sq/meters, about 4 kg of fertilizer required