SOLUTION: Find, in simplest radical form, the shortest possible distance in centimeters that could be traced from A to B on the surface of this 12 cm x 16 cm x 36 cm block. https://ibb.

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Question 1200556: Find, in simplest radical form, the shortest possible
distance in centimeters that could be traced from A to B
on the surface of this 12 cm x 16 cm x 36 cm block.
https://ibb.co/SPd5gsB

Found 2 solutions by Solver92311, ikleyn:
Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!


The shortest path will be along one of the edges and then diagonally across one of the faces. You get the most bang for your buck by crossing the largest face on the
diagonal. So:

Recognizing that and , we can say and then the total shortest distance from A to B is cm.

John

My calculator said it, I believe it, that settles it

From
I > Ø

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find, in simplest radical form, the shortest possible
distance in centimeters that could be traced from A to B
on the surface of this 12 cm x 16 cm x 36 cm block.
https://ibb.co/SPd5gsB
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Unfold the parallelepiped/(the block) on a plane and draw a straight line 
connecting the points A and B on the unfold.


    +------------------------------------------------------------+
    |   The segment AB on the plane is the shortest distance.    |
    +------------------------------------------------------------+


On the unfold, you have right-angled triangle with the legs  (36+12) = 48 cm and 16 cm
and the hypotenuse AB.


Now it is easy to calculate the distance 

    d = sqrt%28%2836%2B12%29%5E2%2B+16%5E2%29 = sqrt%2848%5E2+%2B+16%5E2%29 = sqrt%2816%5E2%2A%283%5E2%2B1%29%29 = 16%2Asqrt%2810%29.


It is about  50.6 cm.


Compare it with the solution by the other tutor  4%2Asqrt%2897%29%2B12 = 51.4 cm (approximately).

Solved.