Question 1199951: Assuming that two holes go all the way through and the third
only halfway through, what is the total number of faces of the solid?
https://ibb.co/M5BScx6
I got 26, but I think that's wrong...
Thanks!
Found 3 solutions by Solver92311, math_tutor2020, ikleyn:
Answer by Solver92311(821)   (Show Source):
Answer by math_tutor2020(3816)  (Show Source):
You can put this solution on YOUR website!
The cube starts off with 6 faces.
Drill a hole all the way through and we introduce 4 more inner faces. These are the inner walls of the tunnel.
If another hole is drilled through all the way, then another 4 inner walls or faces emerge.
A third hole is drilled, but not all the way through. This introduces 4+1 = 5 faces.
The 4 are the walls of this hole, and the +1 at the end refers to the floor so to speak. Imagine that this hole is a crater that you can stand in.
Total = 6 + 4+4+4 + 1 = 19 faces
Answer: 19
Answer by ikleyn(52780)  (Show Source):
You can put this solution on YOUR website! .
I can think that this parallelepiped represents a three-store building
with the horizontal corridors at the second floor, going
South-North and West-East directions and intersecting at the central hall.
Also, there is an elevator from the first floor (a garage) to the central
hall at the second floor.
Then the South-North corridor contributes 2*4 = 8 faces;
the West-East corridor contributes 2*4 = 8 faces;
the elevator contributes 4 faces;
and the building itself contributes 6 faces.
The total faces is then 6 + 8 + 8 + 4 = 26. ANSWER
Solved.
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So, the answer depends on a description of the problem.
An adequate description ABSENTS in your post, leaving a room
for different assumptions/interpretations/solutios/answers.
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