SOLUTION: An architect wants to draw a rectangle with a diagonal of 13 centimeters. The length of the rectangle is to be 3 centimeters more than triple the width. What dimensions should she

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: An architect wants to draw a rectangle with a diagonal of 13 centimeters. The length of the rectangle is to be 3 centimeters more than triple the width. What dimensions should she       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1195773: An architect wants to draw a rectangle with a diagonal of 13 centimeters. The length of the rectangle is to be 3 centimeters more than triple the width. What dimensions should she make the rectangle?

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

a diagonal d=13 centimeters
if the length of the rectangle L is to be 3 centimeters more than triple+ the width W, we have

L=3W%2B3.....eq1
using Pythagorean theorem we know that
d%5E2=L%5E2%2BW%5E2
substituting d=13 and L=3W%2B3 we have
13%5E2=%283W%2B3%29%5E2%2BW%5E2
169=9W%5E2+%2B+18W+%2B+9%2BW%5E2
10W%5E2+%2B+18W+%2B+9-169=0
10W%5E2+%2B+18W+-160=0 .....factor
2+%28W+%2B+5%29+%285+W+-+16%29+=+0
solutions;
W+%2B+5=0 -> W+=-+5 -> disregard negative solution
%285+W+-+16%29+=+0 ->W+=16%2F5->exact solution
now find the length:
L=3%2816%2F5%29%2B3.....eq1
L=63%2F5->exact solution

dimensions of the rectangle : +63%2F5 centimeter by +16%2F5centimeter