Question 1193706: Mike has 185 pesos in 5-peso and 10-peso coins. He has one less 10 peso coin than 5-peso coins. How many of each type of coin does he have? Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
Mike has 185 pesos in 5-peso and 10-peso coins. He has one less 10 peso coin than 5-peso coins.
How many of each type of coin does he have?
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To solve the problem mentally, take off one 5-peso coin apart, for a minute.
You will have a collection of 180 pesos total, consisting of equal amount of 5-peso coins and 10-peso coins.
Group these coins in sets containing one 5-peso coin and one 10-peso coin.
Each set is worth 5+10 = 15 pesos, and the number of such groups is = 12.
Hence, there were 12 10-peso coins and 13 5-peso coins in the original collection. ANSWERCHECK. 12*10 + 13*5 = 120 + 65 = 185 pesos, in total. ! Correct !
You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.
A convenient place to quickly observe these lessons from a "bird flight height" (a top view) is the last lesson in the list.
Read them and become an expert in solution of coin problems.
