SOLUTION: The length of the hypotenuse of a right triangle is 37 cm and it's area is 210cm^2.Find the length of the legs of the right triangle.

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Question 1187106: The length of the hypotenuse of a right triangle is 37 cm and it's area is 210cm^2.Find the length of the legs of the right triangle.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The length of the hypotenuse of a right triangle is 37 cm and it's [sic] area is 210cm^2.Find the length of the legs of the right triangle.
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it's = it is
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a%5E2+%2B+b%5E2+=+37%5E2+=+1369
a*b/2 = 210 ---> b = 420/a
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a%5E2+%2B+%28420%2Fa%29%5E2+=+1369
a%5E4+%2B+420+=+1369a%5E2
a%5E4+-+1369a%5E2+%2B+420+=+0
Sub x for a^2
x%5E2+-+1369x+%2B+420+=+0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-1369x%2B420+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-1369%29%5E2-4%2A1%2A420=1872481.

Discriminant d=1872481 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--1369%2B-sqrt%28+1872481+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-1369%29%2Bsqrt%28+1872481+%29%29%2F2%5C1+=+1368.69313793694
x%5B2%5D+=+%28-%28-1369%29-sqrt%28+1872481+%29%29%2F2%5C1+=+0.306862063057565

Quadratic expression 1x%5E2%2B-1369x%2B420 can be factored:
1x%5E2%2B-1369x%2B420+=+%28x-1368.69313793694%29%2A%28x-0.306862063057565%29
Again, the answer is: 1368.69313793694, 0.306862063057565. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1369%2Ax%2B420+%29