SOLUTION: The width of the rectangle is 0.4 meters less than the length. The perimeter of a rectangle is 53.2 meters. Find the dimensions of the rectangle (in meters). length 13.

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Question 1186419: The width of the rectangle is 0.4 meters less than the length. The perimeter of a rectangle is 53.2 meters. Find the dimensions of the rectangle (in meters).
length
13.
Found 2 solutions by Alan3354, JBnovelwriter:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The width of the rectangle is 0.4 meters less than the length. The perimeter of a rectangle is 53.2 meters. Find the dimensions of the rectangle (in meters).
length
----------------
P = 2W + 2L = 53.2
W + L = 26.6
L = W + 0.4
------------------------
Sub for L in the 1st equation

Answer by JBnovelwriter(34) About Me  (Show Source):
You can put this solution on YOUR website!
P=2W%2B2L perimeter formula
W=L-0.4
P=53.2
Substitute and solve in the perimeter equation
53.2=2%28L-0.4%29%2B2L multiply in parentheses
53.2=2L-0.8%2B2L add like terms
53.2=4L-0.8 add 0.8 to both sides
54=4L divide by 4
highlight%2813.5=L%29
13.5-0.4=W
highlight%2813.1=W%29