Question 1183354: Find the missing measure needed to solve for either the area or perimeter of a rectangle. w=7, l=12, P=
how do you solve of the perimeter or the area in this equation? when I do I end up getting the wrong answer
Found 4 solutions by Boreal, ikleyn, Edwin McCravy, Alan3354:
Answer by Boreal(15235)   (Show Source):
Answer by ikleyn(52780)  (Show Source):
You can put this solution on YOUR website! .
In this problem, there is NO missing measures to find either the area or the perimeter.
All needed measures are in the place and are given to you, so the formulation of the post is non-sensical.
To calculate the perimeter of a rectangle, add the measures of its four sides.
To calculate the area of the rectangle, multiply its length by its width.
What REALLY is, which you do not understand in these simple procedures ?
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Again, as the problem is worded, printed, posted and presented, it is NONSENSICAL.
The correct formulation is THIS:
Given the width of a rectangle W= 7 and the length L= 12, find its perimeter and its area.
In this form, any 2-nd grade student will give you an answer in 5 seconds,
spending 1 second for the area and 4 seconds for the perimeter.
Answer by Edwin McCravy(20055)  (Show Source):
You can put this solution on YOUR website!
Another way is to draw it and count.
The perimeter is the distance around, which is
12 across the top
12 across the bottom
7 down the left side
7 down the right side
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38 is the perimeter
To find the area, count the little squares.
There are 84 little squares, so the area is 84.
Edwin
Answer by Alan3354(69443)  (Show Source):
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