Question 1181435: A sports organization collected data about the shoe sizes of soccer players and hockey players. The dot plots show the data that was collected.
https://lh3.googleusercontent.com/fRqZqtUanbdDZQx61KXMiSR2uPcTACmN-HYtJjChkpHlywGYhwwyN4AIxiWKGjkZf5TVhr_SBdjsfbFhobMxmVeseTEXgRMV0A0Vdh6cPNHy8Fzykol9ttDEzJ93xMeeX-x7eUZ_
How do the medians of the data sets compare in terms of the mean absolute deviations of the data sets?
A. The median shoe size for the hockey players is 1.5 greater than the median shoe size for the soccer players, and the difference is 1.25 times the mean absolute deviation of either data set.
B. The median shoe size for the hockey players is 2 greater than the median shoe size for the soccer players, and the difference is 1.25 times the mean absolute deviation of either data set.
C. The median shoe size for the hockey players is 1.5 greater than the median shoe size for the soccer players, and the difference is 0.9375 times the mean absolute deviation of either data set.
D. The median shoe size for the hockey players is 2 greater than the median shoe size for the soccer players, and the difference is 0.9375 times the mean absolute deviation of either data set.
Is it A, B, C, or D?
Answer by ikleyn(52778)   (Show Source):
You can put this solution on YOUR website! .
I see 4 (four, FOUR) identical posts.
FOUR is TOOOOOOOOOOOOOOOOOOOOO many.
Having two is MORE THAN ENOUGH.
Everything that is greater than 2 - - - IRRITATES.
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