SOLUTION: Graph y = x2 + 5x + 6. Determine the table of values and calculate the first and second differences.

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Question 1179669: Graph y = x2 + 5x + 6. Determine the table of values and calculate the first and second differences.
Found 2 solutions by greenestamps, MathLover1:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Yes; do that....

The instructions are clear; all you need to do is do what it says. It's not our purpose here to do it for you.

One comment.... Since they ask you to calculate the first and second differences, your table of values needs to have consecutive values for x. Keep the values small -- maybe from -3 to +3 or something like that.

If you don't understand what they are asking you to do, here is an example using a similar equation.

y = x^2-3x-4

Table of values (using consecutive "small" values of x):
   x   y=x^2-3x-4
  ----------------
  -2   4+6-4 = 6
  -1   1+3-4 = 0
   0   0+0-4 = -4
   1   1-3-4 = -6
   2   4-6-4 = -6
   3   9-9-4 = -4
   4  16-12-4= 0
   5  25-15-4=6

First and second differences:
    6   0  -4  -6  -6  -4   0   6   (the y values for the consecutive x values)
      -6 -4  -2   0  +2  +4  +6   (first differences: differences between successive y values)
        +2 +2  +2  +2  +2  +2   (second differences: differences between successive first differences)

Presumably one of the things you are supposed to learn from this is that, since the given equation is a polynomial of degree 2, the second differences are constant....


Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Graph y+=+x%5E2+%2B+5x+%2B+6

+graph%28+600%2C+600%2C+-50%2C+50%2C+-10%2C+50%2C+x%5E2+%2B+5x+%2B+6%29+

Determine the table of values and calculate the first and second differences.
x|y
0|6....y+=+0%5E2+%2B+5%2A0+%2B+6=6
1|12....y+=+1%5E2+%2B+5%2A1+%2B+6=12
2|20....y+=+%282%29%5E2+%2B+5%2A%282%29+%2B+6=20
3|30....y+=+%283%29%5E2+%2B+5%2A%283%29+%2B+6=30
4|42....y+=+%284%29%5E2+%2B+5%2A%284%29+%2B+6=42

->the first difference
12-6=6
20-12=8
30-20=10
42-30=12
the first differences are not same, means function is not linear
->the second difference
8-6=2
10-8=2
12-10=2
the second differences are is 2, means we have quadratic model