SOLUTION: Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?

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Question 117900: Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal
of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

If the length L of a rectangle is 1+cm longer than its width W, then we have
L+=+W+%2B+1cm

the diagonal d+=+4cm
since the diagonal cutting a rectangle into two right triangles, we will use Pythagoras Theorem to find what the length and the width are
d%5E2+=+L%5E2+%2B+W%5E2….substitute d and L

%284cm%29%5E2+=+%28W+%2B+1cm%29+%5E2+%2B+W%5E2
16cm%5E2+=+W%5E2+%2B+2Wcm+%2B+1cm%5E2%2B+W%5E2
16cm%5E2+=+2W%5E2+%2B+2Wcm+%2B+1cm%5E2
16cm%5E2+%96+%281cm%29%5E2=+2W%5E2+%2B+2Wcm+
15cm%5E2+=+2W%5E2+%2B+2Wcm+
+0=2W%5E2+%2B+2Wcm+%96+15cm%5E2+….now we can use quadratic formula to solve for W
Since a=2, b=2, and c+=+-15, we will have:
W%5B1%2C2%5D=%28-2+%2B-+sqrt+%282%5E2+-4%2A2%2A%28-15%29+%29%29+%2F+%282%2A2%29
W%5B1%2C2%5D=%28-2+%2B-+sqrt+%284+%2B+120+%29%29+%2F+4

W%5B1%2C2%5D=%28-2+%2B-+sqrt+%28124+%29%29+%2F+4
W%5B1%2C2%5D=%28-2+%2B-+11.14+%29+%2F+4
Since we are looking for width, we need only positive solution:
W%5B1%5D=%28-2+%2B+11.14+%29+%2F+4
W%5B1%5D=%28+9.14+%29+%2F+4
W%5B1%5D+=+%282.285%29cm

Then
L+=+W+%2B+%281cm%29
L+=+%282.285%29cm+%2B+%281cm%29
L+=+%283.285%29cm+
Check:
d%5E2+=+L%5E2+%2B+W%5E2….
d=+sqrt%28L%5E2+%2B+W%5E2%29….

4+=+sqrt%28%283.285%29%5E2+%2B+%28%282.285%29%5E2%29%29….
4+=+sqrt%28+10.79+%2B+5.22%29….
4+=+sqrt%28+16%29….
4+=+4….