SOLUTION: The lengths of the diagonals of a rhombus are 14 and 16. Find the measure of the length of the sides of a rhombus.

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Question 1177620: The lengths of the diagonals of a rhombus are 14 and 16. Find the measure of the length of the sides of a rhombus.
Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

Area of Rhombus = (1/2) diagonal1 * diagonal 2
= (1/2) * 14*16
=112 cm^2

Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.


            It looks like  @mananth did not read the post,  at all.

            Otherwise,  he  (or she)  would not write something  IRRELEVANT  to the problem.

            I came to bring you the correct solution and the correct answer.


The diagonals of a rhombus (of any rhombus) cut it in 4 (four) congruent right-angled triangles.


One leg of such triangle is half of one diagonal.

The other leg of such triangle is half of the other diagonal.


So, you have 4 right-angled triangles with the legs of 7 and 8 units each.


Then the hypotenuse of each such a triangle is  sqrt%287%5E2%2B8%5E2%29 = sqrt%2849%2B64%29 = sqrt%28113%29 = 10.63 units (rounded).


It is the side length of any of 4 (four) sides of the rhombus.    ANSWER

Solved.


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For your safety,  ignore the post by  @mananth,  since it is  IRRELEVANT  to the problem.


As  I  just said several years ago,  @mananth needs two helpers to work at this forum successfully:

        - one assistant to read the problems to him  (or to her)  and explain their meaning,

        - and the other assistant to edit and re-write his  (or her)  solutions after him  (or her).


Currently,  I alone perform the duties of these two assistants.

And I can not say that I am extremely happy of it . . .