SOLUTION: A rock was thrown upwards off of a seaside cliff and fell down to the beach below.
Its motion was described by h = −16t² + 16t +125 where h is the vertical distance above the b
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Its motion was described by h = −16t² + 16t +125 where h is the vertical distance above the b
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Question 1177208: A rock was thrown upwards off of a seaside cliff and fell down to the beach below.
Its motion was described by h = −16t² + 16t +125 where h is the vertical distance above the beach in meters and t is time after throwing in seconds.
What was the height of the cliff? How can you tell?
How can you tell that the motion of the rock had a maximum height?
Show how to convert the equation in standard form to the vertex form using the method of completing the square.
What was the vertex of the throw?
What was the maximum height of the rock?
How much time had passed since the throw when the maximum height was reached?
When did the rock hit the beach below?
At what time(s) did the rock reach a height of 127m?
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