SOLUTION: The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle. Thanks so much!

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Question 116850:
The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle.
Thanks so much!
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
L=2W+10
32=2(2W+10)+2W
32=4W+20+2W
32=6W+20
6W=32-20
6W=12
W=12/6
W=2 ANSWER FOR THE WIDTH.
L=2*2+10
L=4+10
L=14 ANSWER FOR THE LENGTH.
PROOF
2*2+2*14=32
4+28=32
32=32