SOLUTION: Find the equation of a parabola with axis parallel to the x-axis and passing through (3/2, 1), (5,0) and (-1,2).
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Question 1167090
:
Find the equation of a parabola with axis parallel to the x-axis and passing through
(3/2, 1), (5,0) and (-1,2).
Answer by
Boreal(15235)
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x=ay^2+by+c
3/2=a+b+c
5=c
-1=4a+2b+c
4a+2b=-6 and
a+b=-3.5
-2a-2b=7
2a=1
a=1/2
b=-4
x=(1/2)y^2-4y+5