SOLUTION: The rectangle shown has a perimeter of 62 cm and the given area. Its length is 4 more than twice its width. Write and solve a system of equations to find the dimensions of the rect

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Question 1154102: The rectangle shown has a perimeter of 62 cm and the given area. Its length is 4 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle.The area is 198 cm squared. What is the width and length of the rectangle
Answer by MathLover1(20849) About Me  (Show Source):
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The area of the rectangle is:
A=L%2AW
The perimeter of the rectangle is:
P=2%28L%2BW%29
if the perimeter of 62 cm
2%28L%2BW%29=62
L%2BW=62%2F2
L%2BW=31.......eq.1
and if its length is 4 more than twice its width, we have
L=2W%2B4......eq.2
then
2W%2B4%2BW=31
3W=31-4
3W=27
W=9cm
go to eq.2, substitute W
L=2%2A9%2B4......eq.2
L=22cm

the area is 22cm%2A9cm=198cm%5E2