Question 115369This question is from textbook
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An architect has designed a motel pool within a rectangular area that is fenced on three sides as shown in the figure. If she uses 60 yards of fencing to enclose an area of 352 square yards, then what are the dimensions for Length and Width assuming that length is greater than width.
This question is from textbook
Answer by rajagopalan(174)   (Show Source):
You can put this solution on YOUR website! Circumference of 3 sides=2L+B=60 yards
area of rectangle= 352 square yards
Let the dimensions for Width=x
Then length=352/x
2x+(352/x)=60
multiply throghout by x,
2x^2+352=60x
2x^2-60x+352=0
x^2-30x+176=0 ...(dividing thro by 2)
x^2-22x-8x-16=0
x(x-22)-8(x-22)=0
(x-8)(x-22)=0
x=22 or 8,
When x=8
2x+352/x=60
16+352/8=60
16+44=60 ok
Then Width=8
Length=352/8=44
Answer ..Length=44, width=8
okay
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