SOLUTION: The base of a triangle is 1 inch longer than twice each of the other two sides, which are the same. If the perimeter of the triangle is 25 inches, what are the lengths of each side

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Question 1145837: The base of a triangle is 1 inch longer than twice each of the other two sides, which are the same. If the perimeter of the triangle is 25 inches, what are the lengths of each side?
Found 3 solutions by josgarithmetic, ikleyn, richwmiller:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Side lengths:
y, y, and 2y+1

Perimeter 25

%282y%2B1%29%2B2y=25
You continue from here.

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
The base of a triangle is 1 inch longer than twice each of the other two sides, which are the same.
If the perimeter of the triangle is 25 inches, what are the lengths of each side?
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Such a triangle DOES NOT exists and CAN NOT exist.

It is a FAKE problem.





Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
It is an impossible triangle because the sum of the lengths of any two sides of a triangle must be greater than the third side.
Tutor josgarithmetic response is relevant. It will result in 6,6,13 which means it is impossible for the given reason.