SOLUTION: If the sides of a square are decreased by 2cm, the area is decreased by 36 cm squared. What were the dimensions of the original square?

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Question 114394: If the sides of a square are decreased by 2cm, the area is decreased by 36 cm squared. What were the dimensions of the original square?
Answer by solver91311(24713) About Me  (Show Source):
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Start with defining a variable to represent the length of a side of the original square, let's call it x.
So the area of the original square would be A%5Bo%5D=x%5E2.

The new square is 2 cm shorter on each side, so one of the sides must measure x-2, and the area of the new square must be A%5Bn%5D=%28x-2%29%5E2.

But we know that A%5Bo%5D=A%5Bn%5D%2B36cm%5E2. Substituting: x%5E2=%28x-2%29%5E2%2B36.

Now, expand the binomial, collect terms, and put the equation in standard form.

x%5E2=x%5E2-4x%2B4%2B36
x%5E2-x%5E2=x%5E2-x%5E2-4x%2B40
-4x%2B40=0
-4x=-40
x=10

So the original square was 10 cm on a side.

Let's check the answer.

Original area 10%5E2=100
New area 8%5E2=64
100-64=36, Check.