SOLUTION: Betsy, a recent​ retiree, requires ​$6,000 per year in extra income. She has ​$60,000 to invest and can invest in​ B-rated bonds paying 13​% per year or in a certifica

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Betsy, a recent​ retiree, requires ​$6,000 per year in extra income. She has ​$60,000 to invest and can invest in​ B-rated bonds paying 13​% per year or in a certifica      Log On

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Question 1137202: Betsy, a recent​ retiree, requires ​$6,000 per year in extra income. She has ​$60,000 to invest and can invest in​ B-rated bonds paying
13​% per year or in a certificate of deposit​ (CD) paying
5​% per year. How much money should be invested in each to realize exactly ​$6,000 in interest per​ year?

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


(1) Algebraically....

x amount at 13% and the rest of the $60,000 at 5%; the total interest is the sum of the amounts of interest from each investment:
.13%28x%29%2B.05%2860000-x%29+=+6000

Basic algebra; complicated a bit by the decimals; I leave it to you to find the solution by that method.

(2) A much easier and faster way to solve "mixture" problems like this....

(a) The $6000 interest she wants is 10% of the $60,000.
(b) 10% is 5/8 of the way from the lower percentage of 5% to the higher percentage of 13%. (13-5 = 8; 10-5 = 5; so 10% is 5/8 of the way from 5% to 13%).
(c) That means 5/8 of the money needs to be invested at the higher rate.

ANSWER: 5/8 of $60,000 = $37,500 at 13%; the rest, $22,500, at 5%.

CHECK:
.13%2837500%29%2B.05%2822500%29+=+6000