.
The area of the flower bed is 30*24 = 720 square yards.
1/4 of it is
= 180 square yards.
Let x be the uniform width of the walkway around the flower bed.
Then the outer dimensions of the larger rectangle are (30+2x) and (24+2x) yards,
so the area of the larger rectangle is (30+2x)*(24+2x).
From the condition, we are given that
(30+2x)*(24+2x) - 30*24 = 180 (it is exactly the area of the path !)
Simplify
30*24 + 48x + 60x + 4x^2 - 30*24 = 180,
4x^2 + 108x - 180 = 0,
x^2 + 27x - 45 = 0.
=
=
=
.
Of the two roots, choose the positive x =
= 1.57,
since only positive root makes sense.
ANSWER. The walkway's uniform width is 1.57 yards.
CHECK. (30+2*1.57)*(24+2*1.57) - 30*24 = 179.4 square yards.
Taking rounding into account, it is good solution.
Solved.
-----------------
It is one of many typical problems of this kind.
From my solution, you need to learn TWO things:
1) The outer dimensions of the larger rectangle are 2x enlarged dimensions of the base rectangle, and
2) Learn how to create the base equation to find the unknown "x".
The rest is just a technique.
To see many other similar solved problems, look into the lessons
- Problems on the area and the dimensions of a rectangle surrounded by a strip
- Cynthia Besch wants to buy a rug for a room
- Problems on a circular pool and a walkway around it
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic
"Dimensions and the area of rectangles and circles and their elements".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.