SOLUTION: a football is thrown into the air from an initial height of 4 feet with an upward velocity of 46 ft/sec. The function h=-16t^2+46t+4 gives the height after t sec. what’s the balls
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Question 1131313: a football is thrown into the air from an initial height of 4 feet with an upward velocity of 46 ft/sec. The function h=-16t^2+46t+4 gives the height after t sec. what’s the balls maximum height Answer by ikleyn(52781) (Show Source):
They want you find the maximum of the quadratic function h(t) = -16*t^2 + 46t + 4 as the function of variable "t".
For any quadratic function of the general form f(x) = ax^2 + bx + c with negative coefficient "a", its maximum is achieved at x = .
In your case a = -16, b= 46. Hence, the given function h(t) achieves the maximum at t = = = seconds.
To find the maximum value of h(t), substitute this value t= into the formula for h(t) and calculate
= = = 37.06 ft (approximately).
Answer. The maximum height is 37.06 ft (approximately, with two valid decimal places after the decimal point).
