SOLUTION: Find the dimensions of the box described. The length is twice as long as the width. The height is 4 inches greater than the width. The volume is 48 cubic inches.

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Question 1127660: Find the dimensions of the box described.
The length is twice as long as the width. The height is 4 inches greater than the width. The volume is 48 cubic inches.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

+LWH+=+48+
Using L=2W and H=W+4:
+%282W%29%28W%29%28W%2B4%29+=+48+
++2W%5E3+%2B+8W%5E2+=+48+
++W%5E3+%2B+4W%5E2+-+24+=+0+

The only real valued solution is W=2
W=2 —> L=4
W=2 —> H=6
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Ans: W=2in, L=4in, H=6in
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Check: 2*4*6 = 48